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Who gets most money?
You 80%  80%  [ 4 ]
David 0%  0%  [ 0 ]
I can't answer this question 20%  20%  [ 1 ]
Total votes : 5

MathematicalOwl
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22 Aug 2014, 11:55 am

This is the beginning of a weird maths puzzle story which I found in a notebook under my bed.

Quote:
You are waiting for the train when you hear your mobile phone ringing. You look in your bag. You can't find your phone because your sandwiches have spread themselves everywhere. You remove the solid bits and look again, but you are distracted by finding another bag inside yours. It has several round glass beads of various diameters. You are not sure what to do with them. You don't even remember where you got the bag from. The label says, "85 fine round glass beads. Diameter unknown. 1.5cm long holes. Excellent quality. May be cursed."

Your beads look like this
Image


David (you know him, don?t you?) also has a bag. He won?t let you touch it. He remembers that he was given them by a mysterious person who he is unable to describe. His label says, "175 excellent round glass beads. Diameter not known. 1cm long holes. Fine quality. Possibly cursed."

His beads look like this
Image

You and David are discussing how to dispose of the beads when you are interrupted by a weird dwarf. He offers to buy the beads, and says he will pay by weight.

Assuming that the label on your bag is correct (you didn't count and measure them, unlike David), who will get the most money?

By the way, you missed the train. And you should answer your phone.



Spiderpig
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24 Aug 2014, 7:46 am

That?s ? funny :) I wonder how you solved it. The very fact that it?presumably?can be solved might be a good clue to get the right answer quickly in your head bypassing the calculations needed to actually work out each bead?s volume. I only realized this after doing it, though.

It seems like you?re doing justice to your nickname :P

EDIT ? Well, I?m assuming the density of David?s beads is the same as that of yours. Who knows if the difference between ?fine? and ?excellent? quality, or curses, mean a difference in density!


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MathematicalOwl
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24 Aug 2014, 11:03 am

The glass is all the same density. I'm rewriting the story to make things like that clearer, and then I'm going to give it to my friends and watch them struggle. :twisted:

Some useful formulae (only one is actually needed, but the others are useful anyway)

Volume of a sphere (radius R): Image

Volume of a cylinder (radius r, height h): Image

Volume of a spherical cap (height h) in a sphere of radius a: Image

Edit: Forgot to say what R, r and h mean.



Last edited by MathematicalOwl on 25 Aug 2014, 10:32 am, edited 1 time in total.

trollcatman
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24 Aug 2014, 2:30 pm

^^^ You might want to define what r, R, and h are.



MathematicalOwl
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25 Aug 2014, 10:30 am

Thanks for pointing that out. I should probably get more sleep before posting anything else.



morslilleole
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25 Aug 2014, 1:48 pm

How does the possible curse fit into the equation?


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Spiderpig
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25 Aug 2014, 3:29 pm

I think it?s actually less cumbersome to calculate a bead?s volume as ?

http://pastebin.com/EDKkhZ6H (encrypted so it doesn?t spoil the problem).

morslilleole wrote:
How does the possible curse fit into the equation?


That seems a case of ?My normal approach is useless here?.


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MathematicalOwl
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26 Aug 2014, 8:08 am

morslilleole wrote:
How does the possible curse fit into the equation?


That comes up later in the story, with the return of the weird dwarf.



naturalplastic
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27 Aug 2014, 6:56 am

Who ever has the most "tonnage" of beads gets the most money.

The problem is that you have a smaller number of heavier beads, but David has a bigger number of lighter beads.

Glass is glass (we can assume). So the density of the beads can be assumed to be the same. The curse is probably a red herring.

Thats the set up of the problem. Pretty simple.

But doing the calculations to answer it is quite complicated. You need to calculate the volume of the spheres, minus the volumes of the cylinders cut out of them, and the volume of the caps taken off the tops.

Just looking at the diagrams it looks like each of your beads has more than twice the volume of glass that each of David's have. So even though he has twice as many beads you would get the most money. But thats just a guesstimate.



Spiderpig
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27 Aug 2014, 10:28 am

naturalplastic wrote:
Just looking at the diagrams it looks like each of your beads has more than twice the volume of glass that each of David's have. So even though he has twice as many beads you would get the most money. But thats just a guesstimate.


How do you guesstimate that?

Each bead?s shape is entirely determined by the radius of the ball it was carved from and the height of the cylindrical hole. You?re only given the latter, but this, in itself, is the strong clue I mentioned before.

You could make a rough estimate forgetting about the different shapes and considering that a linear dimension of your beads is 3/2 times that of David?s. As an object is scaled up or down, its volume changes proportionally to the cube of the scaling factor, so each of your beads should have roughly 3³/2³, i.e., 27/8 times the volume of one of David?s, which is very comfortably greater than 175/85.

Nevertheless, since MathematicalOwl posted the formulae for the volumes, the problem is very much solved. If you use them, you can get an accurate calculation to improve the rough estimate above. I think the result is funny, and then you can see how the simple hint that the problem can be solved is a big clue.


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naturalplastic
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27 Aug 2014, 11:20 am

Spiderpig wrote:
naturalplastic wrote:
Just looking at the diagrams it looks like each of your beads has more than twice the volume of glass that each of David's have. So even though he has twice as many beads you would get the most money. But thats just a guesstimate.


How do you guesstimate that?

Each bead?s shape is entirely determined by the radius of the ball it was carved from and the height of the cylindrical hole. You?re only given the latter, but this, in itself, is the strong clue I mentioned before.

You could make a rough estimate forgetting about the different shapes and considering that a linear dimension of your beads is 3/2 times that of David?s. As an object is scaled up or down, its volume changes proportionally to the cube of the scaling factor, so each of your beads should have roughly 3³/2³, i.e., 27/8 times the volume of one of David?s, which is very comfortably greater than 175/85.

Nevertheless, since MathematicalOwl posted the formulae for the volumes, the problem is very much solved. If you use them, you can get an accurate calculation to improve the rough estimate above. I think the result is funny, and then you can see how the simple hint that the problem can be solved is a big clue.

Hmmm..well..

In cross section David's beads appear as one square unit of air, and two tiny slivers of glass totaling maybe a third of the air. But your's appear as one half by one-and-a-half (ie 3/4 of a square unit) of air, plus about an equal amount of glass. So thats 33 percent of a square unit vs 75 percent of a square unit. Eighty five times 75 percent is about 64, and 175 times 33.3 percent is 58. So even in two dimensions "You" have slightly more. In three dimensions the ratio between the two totals would be squared making it more lopsided in your favor. I would think. thats how I guesstimated it.

But when I get a chance Ill roll up my sleeves and do the equations.