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Math-Physics-Linear acceleration

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technojoe
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13 Dec 2009, 1:21 pm

A wee problem for my fellow geeks nerds aand scientists...3774'5 you can join in to :D

This is a linear acceleration problem if you like them i will post more

Quote:
A body leaves point A and moves in a straight line with a constant velocity of 40m/s^-1. Ten seconds later another body wich is at rest at A is given a constant acceleration of 2m/s^-2 and moves in the same direction as the first body. How long does it take for the second body to catch up with the first and how far from A does this occure


Remember!! !

V=U+AT

V^2 = U^2 + AT

S=U+AT^2

answers must be done out in full and mailed to me

Happy Math

JJM


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Jono
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13 Dec 2009, 4:25 pm

Some of your kinematics equations are incorrect. The second one should be:

v^2 = U^2 + AS

The last one should be:

S = UT + (1/2)*AT^2.

Remember, the last one can be derived by calculating the time integral over the first equation. The problem is quite simple but I don't know if I'm allowed to post the solution here. I'll first see what others come up with.



technojoe
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20 Dec 2009, 3:40 pm

Remember!! !

V=U+AT

V^2 = U^2 + 2AS

S=U+(1/2)AT^2

Its linear acceleration not kinematics


Answer is to me MAILED to me (via PM or whatever you call them here)


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ruveyn
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21 Dec 2009, 11:01 am

Solve for t:

v*t = 1/2*a*t^2

then plug in answer in

s = v*t.

Problem solved!

ruveyn



technojoe
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21 Dec 2009, 4:10 pm

Work it out.. so far...incorrect


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