I wrote this a long time ago and thought I would post it. I really don't remember why I wrote it. Enjoy!
Debunking Scientist Statements About Time Travel And Dissecting Time Travel Into Problematic Astrometry Values
A short essay by Ryan Allen
June 19, 2003, 2:08 AM
©2003 Ryan Allen
kxmode1@yahoo.com
Figuratively, time is a wheel.
We know time is visible through the method of past, present and future. Rather than one rigid, unchangeable shape, this time wheel itself has the ability to change and form a complete system where varied speeds of light could be achieved.
Normal time is represented as a wheel with three rings and an inner core. Each successive ring rotates by a small amount compared to the preceded ring (illustrative examples: the ring animation from the movie Contact, or watch runners during a Track and Field event). While the inside ring rotates slowly the outermost ring moves at a high rate of speed. As the wheel rotates, the coordinates (x, y) of a point on the wheel to its center are dynamic, but the distance (r) between the point and the center are static. The following formula is supposed:
Code:
r2 = x2 + y2 = constant
The coordinates (x, y, and z) of the interval between two points in three-dimensional space (a vector) change when the coordinate system is rotated in three dimensions. However the separation (r) of the two points remains constant. Thus we arrive at the formula:
Code:
r2 = x2 + y2 + z2 = constant
This again is what could be classified as normal time.
Here's where things get interesting…
Let's go into different warped times otherwise known as a space-time wheel. A space-time wheel is shaped like the letter "X". A vectored shape becomes horizontal where time (t) is vertical and space (x) is horizontal.
Like the normal three-ringed circular shape, a small velocity compared to the preceded ring, or branch there boosts each successive ring. As the space-time wheel boosts the space-time coordinates (t, x) of a point on the wheel to its center change. Yet the space-time separation(s) among the point and the center remains constant. This formula could best represent this:
Code:
s2 = -t2 + x2 = constant
Moreover, the coordinates (t, x, y, z) of the interval between two events in four-dimensional space-time (a 4-vector) change whenever the coordinate system is boosted or rotated, but the space-time separations of the two events remain constant. This would result in formulating:
Code:
s2 = -t2 + x2 + y2 + z2 = constant
The invariant space-time separation(s) between two events is a rock in the sea of relativity (a quantity that remains the same for all observers). Though time and space they change for different observers. The space-time separation(s) is of basic importance in relativity.
Let's suppose you took a trip across the Universe in a spaceship, constantly accelerating at one-Earth gravity (g). How far would you travel in how much time? The space-time wheel offers a unique way to solve this problem. Because the rotating space-time wheel might be regarded as representing space-time frames, that undergoing constant acceleration, points on the right quadrant of the rotating space-time wheel would represent world lines of persons whom accelerated with constant acceleration in their own frame.
If the units of space and time are chosen so that the speed of light and the gravitational acceleration are one, (c = g = 1), then the proper time experienced by the accelerating person is the boost angle, and the time and space coordinates of the accelerating person (to a person whom remains idle), are those of a point on the space-time wheel:
Code:
(t, x) = (sinh, cosh)
In the case where the acceleration is one-Earth gravity (g = 9.80665 m/s2), the unit of time is [c / g = (299,792,458 m/s) / (9.80665 m/s2) = 0.97 years], just short of one year.
After a slow start, you cover ground at an ever-increasing rate, crossing 50 billion light-years, the distance to the edge of the observable Universe, in just over 25 years of your own time.
Does this mean you go faster than the speed of light? No. From a person’s view on Earth, you never go faster than the speed of light. From your own view, distances along your direction of motion are Lorentz-contracted. So distances that are vast from Earth's view appear much shorter to you.
As the Universe rushes by it never goes faster than the speed of light. This is why stars that we see as being vibrant burned out millions of years ago. Simply stated it took the light that long to reach us.
This rosy picture of being able to flint around the Universe has drawbacks. First, it would take too much energy to keep you accelerating at Earth's Gravity. Second, you would use too much Earth-time traveling around at relativistic speeds. If you took a trip to the edge of the Universe by the time you got back not only would all your friends and relatives be dead, but the Earth would probably be gone, swallowed by the Sun in its red giant phase. The Sun would have exhausted its fuel and shriveled into a cold white dwarf star. The Solar System, having orbited the Galaxy thousand times, would be lost somewhere in the Milky Way.
Also worth noting the Universe is expanding. The distance to the edge of the observable Universe is increasing. So it would actually take longer than expected to reach the edge of the observable Universe. Moreover if the Universe is accelerating, as recent evidence from the Hubble diagram of Type Ia Supernovae suggests (
Supernova Cosmology Project and
High-Z Supernova Search), then you will never be able to reach the edge of the observable Universe regardless of speed.
_________________
A Proud Witness of Jehovah God (
JW.org)
Revelation 21:4 "And [God] will wipe out every tear from their eyes,
and death will be no more, neither will mourning nor outcry nor pain be anymore.
The former things have passed away."